Completing the Square
Basic Completing the Square
Complete the square: $x^2 + 8x$
Identify the coefficient of x: $b = 8$ = Coefficient is 8
Take half of b: $\frac{8}{2} = 4$ = Half is 4
Square the result: $4^2 = 16$ = Need to add 16
Add and subtract this value: $x^2 + 8x + 16 - 16$ = Balance maintained
Factor the perfect square trinomial: $(x + 4)^2 - 16$ = Completed square form
Answer: $x^2 + 8x = (x + 4)^2 - 16$
Solving by Completing the Square
Solve $x^2 + 6x + 2 = 0$ by completing the square
Move the constant to the right: $x^2 + 6x = -2$ = Isolated variable terms
Find the value to complete the square: $\left(\frac{6}{2}\right)^2 = 9$ = Need to add 9
Add to both sides: $x^2 + 6x + 9 = -2 + 9$ = $(x + 3)^2 = 7$
Take the square root of both sides: $x + 3 = \pm\sqrt{7}$ = Two solutions
Solve for x: $x = -3 \pm \sqrt{7}$ = Final answer
Answer: $x = -3 + \sqrt{7}$ or $x = -3 - \sqrt{7}$
Converting to Vertex Form
Write $y = x^2 - 4x + 7$ in vertex form and identify the vertex
Group the x terms: $y = (x^2 - 4x) + 7$ = Grouped
Complete the square inside parentheses: $\left(\frac{-4}{2}\right)^2 = 4$ = Add and subtract 4
Add and subtract inside, then regroup: $y = (x^2 - 4x + 4) + 7 - 4$ = Balance maintained
Factor and simplify: $y = (x - 2)^2 + 3$ = Vertex form
Identify the vertex: Vertex form: $y = (x - h)^2 + k$ = Vertex is $(2, 3)$
Answer: $y = (x - 2)^2 + 3$, vertex at $(2, 3)$
When the Leading Coefficient is Not 1
Complete the square: $2x^2 + 12x + 5$
Factor out the leading coefficient from x terms: $2(x^2 + 6x) + 5$ = Factor out 2
Complete the square inside: $\left(\frac{6}{2}\right)^2 = 9$ = Need 9 inside
Add and subtract 9 inside the parentheses: $2(x^2 + 6x + 9 - 9) + 5$ = Added 9, subtracted 9
Multiply the -9 by 2 and take it out of the parentheses: $2(x^2 + 6x + 9) - 18 + 5$ = Note: $2 \times (-9) = -18$
Factor and combine constants: $2(x + 3)^2 - 13$ = Final vertex form
Answer: $2x^2 + 12x + 5 = 2(x + 3)^2 - 13$
Mistake: Forgetting to add to both sides when solving an equation
Why: When completing the square in an equation, whatever you add to one side must be added to the other side to maintain equality.
Correct: After adding $\left(\frac{b}{2}\right)^2$ to the left, add the same value to the right.
Mistake: Not factoring out the leading coefficient first
Why: When $a \neq 1$ in $ax^2 + bx + c$, completing the square directly gives wrong results.
Correct: First factor out $a$ from the $x^2$ and $x$ terms, then complete the square inside.
Mistake: Using $b$ instead of $\frac{b}{2}$ to complete the square
Why: The formula requires half of the coefficient of $x$, squared.
Correct: Always use $\left(\frac{b}{2}\right)^2$, not $b^2$.
Mistake: Forgetting to multiply when distributing
Why: When $a$ is factored out, the value subtracted inside gets multiplied by $a$.
Correct: In $2(x^2 + 6x + 9 - 9)$, the $-9$ becomes $-18$ when distributed: $2(-9) = -18$.
Projectile Motion
Engineers use completing the square to find the maximum height of a thrown object.
The height of a ball is $h = -5t^2 + 10t + 1.5$ meters. Completing the square: $h = -5(t - 1)^2 + 6.5$. The maximum height is 6.5 meters at $t = 1$ second.
Architecture and Design
Architects use completing the square to design parabolic arches and find their highest point.
A bridge arch follows $y = -0.01x^2 + 2x$ (in meters). Converting to vertex form: $y = -0.01(x - 100)^2 + 100$. The arch reaches 100 meters high at its center, 100 meters from its start.
Economics and Profit Optimization
Businesses use quadratic models to find the price that gives the maximum profit.
A company's profit is $P = -2x^2 + 40x - 150$ dollars, where $x$ is the price in dollars. Vertex form: $P = -2(x - 10)^2 + 50$. The maximum profit of 50 dollars comes at a price of 10 dollars.
Completing the square transforms $x^2 + bx$ into $(x + \frac{b}{2})^2 - (\frac{b}{2})^2$
The key value to add is always $\left(\frac{b}{2}\right)^2$
When $a \neq 1$, factor out $a$ from the $x$-terms first
Vertex form $a(x - h)^2 + k$ reveals the vertex $(h, k)$ directly
This technique can solve any quadratic equation, even when factoring fails
Q: When should I use completing the square instead of factoring?
A: Use completing the square when: (1) the quadratic doesn't factor nicely with integers, (2) you need to find the vertex of a parabola, or (3) you're deriving the quadratic formula. Factoring is faster when it works, but completing the square always works.
Q: Why do we add and subtract the same value?
A: Adding and subtracting the same value is like adding zero, which doesn't change the expression's value. This lets us create a perfect square trinomial without changing what the expression equals.
Q: How is this related to the quadratic formula?
A: The quadratic formula is derived by completing the square on the general form $ax^2 + bx + c = 0$. The formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ comes directly from this process!
Completing the Square
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Completing the Square
Master the technique of completing the square to solve quadratic equations and rewrite them in vertex form.