Multiplying Radicals

Learn how to multiply square roots and simplify products of radicals using the product property.

Intermediate25 min18 problems
Practice Problems

Definition

To multiply radicals (square roots), we use the Product Property of Radicals:
a⋅b=a⋅b\sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b}
This means we can multiply the numbers under the radical signs and put the result under a single radical.
Key Principle: When multiplying radicals:
  1. 1.Multiply the numbers outside the radicals together
  2. 2.Multiply the numbers inside the radicals together
  3. 3.Simplify the result if possible
General form: ca⋅db=(c⋅d)a⋅bc\sqrt{a} \cdot d\sqrt{b} = (c \cdot d)\sqrt{a \cdot b}

Try it now

What is 2⋅3\sqrt{2} \cdot \sqrt{3}?

Worked Examples

Multiply: 3⋅5\sqrt{3} \cdot \sqrt{5}
1

Apply the product property

3⋅5=3⋅5\sqrt{3} \cdot \sqrt{5} = \sqrt{3 \cdot 5} → 15\sqrt{15}
2

Check if we can simplify

15 = 3 × 5 (no perfect square factors) → Cannot simplify further
3

Write final answer

3⋅5\sqrt{3} \cdot \sqrt{5} → 15\sqrt{15}

Common Mistakes

Adding radicands instead of multiplying: 3⋅5=8\sqrt{3} \cdot \sqrt{5} = \sqrt{8}

Why it's wrong: The product property says we MULTIPLY the numbers under the radicals, not add them.

Correct: 3⋅5=3⋅5=15\sqrt{3} \cdot \sqrt{5} = \sqrt{3 \cdot 5} = \sqrt{15}

Forgetting to multiply coefficients: 23⋅45=152\sqrt{3} \cdot 4\sqrt{5} = \sqrt{15}

Why it's wrong: Coefficients must be multiplied separately from the radicals.

Correct: 23⋅45=(2⋅4)3⋅5=8152\sqrt{3} \cdot 4\sqrt{5} = (2 \cdot 4)\sqrt{3 \cdot 5} = 8\sqrt{15}

Not simplifying the final answer: 2⋅8=16\sqrt{2} \cdot \sqrt{8} = \sqrt{16}

Why it's wrong: Always check if the result can be simplified! 16=4\sqrt{16} = 4

Correct: 2⋅8=16=4\sqrt{2} \cdot \sqrt{8} = \sqrt{16} = 4

Thinking (23)2=2⋅3=6(2\sqrt{3})^2 = 2 \cdot 3 = 6

Why it's wrong: When squaring 232\sqrt{3}, you must square BOTH the coefficient and the radical.

Correct: (23)2=22⋅(3)2=4⋅3=12(2\sqrt{3})^2 = 2^2 \cdot (\sqrt{3})^2 = 4 \cdot 3 = 12

Interactive Visual

Simplifying Radicals

6⋅8\sqrt{6} \cdot \sqrt{8}
Multiply the roots.

Step 1 of 6

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Practice Problems

18 problems
Problem 1 of 18
Easy
What is 2⋅3\sqrt{2} \cdot \sqrt{3}?

Why It Matters

Multiplying radicals is essential in many areas of mathematics:
  • Geometry: Calculate areas and distances involving irrational numbers
  • Physics: Work with formulas containing square roots (like kinetic energy or wave equations)
  • Engineering: Simplify complex expressions in calculations
  • Higher Mathematics: Foundation for working with complex numbers and polynomial operations
Without this skill, simplifying expressions like (2+3)2(\sqrt{2} + \sqrt{3})^2 would be impossible!

Real World Applications

Geometry: Area of a Square

When the side length involves a radical, finding the area requires multiplying radicals.

Example:

A square has side length 5\sqrt{5} meters. Its area is (5)2=5(\sqrt{5})^2 = 5 square meters.

1Try It Yourself

A square garden has a side length of 323\sqrt{2} meters.

What is the area of the garden?

Step 1: Write the mathematical expression

Area = (32)2(3\sqrt{2})^2

Geometry: Area of a Rectangle

Side lengths found with the Pythagorean theorem are often square roots. The area of a rectangle with such sides is a product of radicals.

Example:

A rectangular rug is 2\sqrt{2} meters wide and 8\sqrt{8} meters long. Its area is 2⋅8=16=4\sqrt{2} \cdot \sqrt{8} = \sqrt{16} = 4 square meters.

2Try It Yourself

A rectangular wall mural is 232\sqrt{3} meters high and 48\sqrt{48} meters wide.

What is the area of the mural in square meters?

Step 1: Write the mathematical expression

Area = 23⋅482\sqrt{3} \cdot \sqrt{48}

Key Takeaways

  • 1The Product Property: a⋅b=a⋅b\sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b}
  • 2Multiply coefficients together and radicands together: ca⋅db=(cd)abc\sqrt{a} \cdot d\sqrt{b} = (cd)\sqrt{ab}
  • 3Always simplify your final answer by finding perfect square factors
  • 4When you square a radical: (a)2=a(\sqrt{a})^2 = a
  • 5When squaring with a coefficient: (ca)2=c2⋅a(c\sqrt{a})^2 = c^2 \cdot a

Frequently Asked Questions

Yes! The product property works for any non-negative numbers under the radicals. Just remember: a⋅b=ab\sqrt{a} \cdot \sqrt{b} = \sqrt{ab}, then simplify if possible.
Yes! The product property works for any non-negative numbers under the radicals. Just remember: a⋅b=ab\sqrt{a} \cdot \sqrt{b} = \sqrt{ab}, then simplify if possible.
Both are correct! (5)2=5⋅5=25=5(\sqrt{5})^2 = \sqrt{5} \cdot \sqrt{5} = \sqrt{25} = 5. The square root and squaring are inverse operations, so they cancel out.
Look for perfect square factors! Factor the number and pull out any squares. For example, 200=100⋅2=102\sqrt{200} = \sqrt{100 \cdot 2} = 10\sqrt{2}.

Glossary

Radical
A mathematical expression containing a root symbol (\sqrt{})
Radicand
The number or expression inside the radical sign (e.g., 5 in 5\sqrt{5})
Coefficient
The number multiplied in front of a radical (e.g., 3 in 323\sqrt{2})
Product Property
The rule that a⋅b=ab\sqrt{a} \cdot \sqrt{b} = \sqrt{ab}
Simplify
To rewrite a radical with the smallest possible radicand

Formula Card

Product Property

a⋅b=a⋅b\sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b}

Multiply radicands

With Coefficients

ca⋅db=(c⋅d)a⋅bc\sqrt{a} \cdot d\sqrt{b} = (c \cdot d)\sqrt{a \cdot b}

Multiply coefficients separately

Squaring a Radical

(a)2=a(\sqrt{a})^2 = a

Square root and square cancel

Squaring with Coefficient

(ca)2=c2⋅a(c\sqrt{a})^2 = c^2 \cdot a

Square both parts

Today's challengeOne problem, three tries

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