Adding Rational Expressions (Unlike Denominators)

Learn how to add rational expressions with different denominators by finding the LCD.

Advanced25 min17 problems
Practice Problems

Definition

To add rational expressions with unlike denominators, we must first find a common denominator. The process is similar to adding numerical fractions:
ab+cd=ad+bcbd\frac{a}{b} + \frac{c}{d} = \frac{ad + bc}{bd}
For rational expressions, we:
  1. 1.Factor each denominator completely
  2. 2.Find the LCD (Least Common Denominator)
  3. 3.Rewrite each fraction with the LCD
  4. 4.Add the numerators
  5. 5.Simplify if possible
2x+1+3x−1=2(x−1)+3(x+1)(x+1)(x−1)=5x+1x2−1\frac{2}{x+1} + \frac{3}{x-1} = \frac{2(x-1) + 3(x+1)}{(x+1)(x-1)} = \frac{5x+1}{x^2-1}

Try it now

What is the LCD of 1x\frac{1}{x} and 1x+2\frac{1}{x+2}?

Worked Examples

Simplify: 2x+3+5x−2\frac{2}{x+3} + \frac{5}{x-2}
1

Identify the denominators

Denominator 1: (x+3)(x+3), Denominator 2: (x−2)(x-2) → Both are linear, no common factors
2

Find the LCD

LCD = (x+3)(x−2)(x+3)(x-2) → Multiply the distinct factors
3

Rewrite first fraction

2x+3⋅x−2x−2=2(x−2)(x+3)(x−2)\frac{2}{x+3} \cdot \frac{x-2}{x-2} = \frac{2(x-2)}{(x+3)(x-2)} → 2x−4(x+3)(x−2)\frac{2x-4}{(x+3)(x-2)}
4

Rewrite second fraction

5x−2⋅x+3x+3=5(x+3)(x+3)(x−2)\frac{5}{x-2} \cdot \frac{x+3}{x+3} = \frac{5(x+3)}{(x+3)(x-2)} → 5x+15(x+3)(x−2)\frac{5x+15}{(x+3)(x-2)}
5

Add the numerators

2x−4+5x+15(x+3)(x−2)\frac{2x-4+5x+15}{(x+3)(x-2)} → 7x+11(x+3)(x−2)\frac{7x+11}{(x+3)(x-2)}

Common Mistakes

Forgetting to factor denominators first

Why it's wrong: Without factoring, you might miss common factors and create an LCD that is larger than necessary, making the problem harder.

Correct: Always factor each denominator completely before finding the LCD. For example, x2−9=(x+3)(x−3)x^2-9 = (x+3)(x-3).

Adding denominators instead of finding LCD

Why it's wrong: Unlike numerators, denominators are not added together. The LCD must contain all factors from each denominator.

Correct: 1x+2+1x+3≠22x+5\frac{1}{x+2} + \frac{1}{x+3} \neq \frac{2}{2x+5}. The LCD is (x+2)(x+3)(x+2)(x+3).

Forgetting to multiply both numerator and denominator

Why it's wrong: When converting to the LCD, you must multiply by a form of 1 (same expression over itself) to keep the value unchanged.

Correct: 2x+1=2(x−1)(x+1)(x−1)\frac{2}{x+1} = \frac{2(x-1)}{(x+1)(x-1)}, not 2(x+1)(x−1)\frac{2}{(x+1)(x-1)}.

Not simplifying the final answer

Why it's wrong: After adding, the resulting numerator might share a common factor with the denominator.

Correct: Always check if the numerator can be factored and if any factors cancel with the denominator.

Watch a video explanation

The same topic explained by another teacher, if a video helps you more.

How to Add and Subtract Rational Expressions | Step-by-Step Examples in Minutes

by Understand The Math

Watch on YouTube

Interactive Visual

1/2
1/3

Interactive Sandbox

Expression Calculator

Try these:

History

No calculations yet

Practice Problems

17 problems
Problem 1 of 17
Easy
What is the LCD of 1x\frac{1}{x} and 1x+2\frac{1}{x+2}?

Why It Matters

Adding rational expressions with unlike denominators appears in many real-world applications:
  • Physics: Combining resistances in parallel circuits: 1Rtotal=1R1+1R2\frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2}
  • Work problems: If one worker completes a job in xx hours and another in yy hours, together they complete 1x+1y\frac{1}{x} + \frac{1}{y} of the job per hour
  • Optics: The thin lens equation: 1f=1do+1di\frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i}
  • Rate problems: Combining different rates of production or travel
Mastering this skill is essential for solving complex algebraic equations and real-world optimization problems.

Real World Applications

Parallel Resistors in Electronics

When resistors are connected in parallel, the total resistance is found using the formula with unlike denominators.

Example:

For two resistors of R1=xR_1 = x ohms and R2=x+2R_2 = x+2 ohms in parallel: 1Rtotal=1x+1x+2=2x+2x(x+2)\frac{1}{R_{total}} = \frac{1}{x} + \frac{1}{x+2} = \frac{2x+2}{x(x+2)}

1Try It Yourself

You have two resistors: one with resistance xx ohms and another with resistance (x+3)(x+3) ohms connected in parallel.

Find an expression for the total resistance.

Step 1: Write the mathematical expression

First find 1Rtotal=1x+1x+3\frac{1}{R_{total}} = \frac{1}{x} + \frac{1}{x+3}

Combined Work Rate Problems

When two people work together, their combined rate involves adding fractions with different denominators.

Example:

If Worker A completes a job in xx hours and Worker B in (x+2)(x+2) hours, their combined rate is 1x+1x+2=2x+2x(x+2)\frac{1}{x} + \frac{1}{x+2} = \frac{2x+2}{x(x+2)} jobs per hour.

2Try It Yourself

Machine A produces a batch in tt hours. Machine B produces the same batch in (t+4)(t+4) hours.

What fraction of the batch do both machines produce together in one hour?

Step 1: Write the mathematical expression

Combined rate = 1t+1t+4\frac{1}{t} + \frac{1}{t+4}

Key Takeaways

  • 1To add rational expressions with unlike denominators, first factor all denominators completely
  • 2Find the LCD by including each factor the maximum number of times it appears in any denominator
  • 3Multiply each fraction by a form of 1 to convert to the LCD
  • 4Add the numerators while keeping the common denominator
  • 5Simplify the result by factoring and canceling common factors

Frequently Asked Questions

Factor each denominator completely. The LCD contains each factor raised to the highest power it appears in any denominator. For example, for 1x2(x+1)\frac{1}{x^2(x+1)} and 1x(x+1)2\frac{1}{x(x+1)^2}, the LCD is x2(x+1)2x^2(x+1)^2.
Factor each denominator completely. The LCD contains each factor raised to the highest power it appears in any denominator. For example, for 1x2(x+1)\frac{1}{x^2(x+1)} and 1x(x+1)2\frac{1}{x(x+1)^2}, the LCD is x2(x+1)2x^2(x+1)^2.
If denominators share factors, include each shared factor only once in the LCD. For example, (x+2)(x−1)(x+2)(x-1) and (x+2)(x+3)(x+2)(x+3) share (x+2)(x+2), so the LCD is (x+2)(x−1)(x+3)(x+2)(x-1)(x+3).
Either form is acceptable. Factored form (x+2)(x−3)(x+2)(x-3) is often preferred because it makes domain restrictions clearer and simplification easier. Expanded form x2−x−6x^2-x-6 may be requested in some contexts.

Glossary

Rational expression
A fraction where the numerator and/or denominator contains a polynomial
LCD (Least Common Denominator)
The smallest expression that is divisible by all denominators in a problem
Unlike denominators
Denominators that are not identical and require finding a common denominator
Factor
To write an expression as a product of simpler expressions

Formula Card

Adding Two Rational Expressions

ab+cd=ad+bcbd\frac{a}{b} + \frac{c}{d} = \frac{ad + bc}{bd}

General formula when denominators have no common factors

LCD Method

aP+bQ=a⋅LCDP+b⋅LCDQLCD\frac{a}{P} + \frac{b}{Q} = \frac{a \cdot \frac{LCD}{P} + b \cdot \frac{LCD}{Q}}{LCD}

Rewrite each fraction using the Least Common Denominator

Today's challengeOne problem, three tries

More in This Topic

Introduction to Rational Expressions

Advanced25 min

Simplifying Rational Expressions

Advanced25 min

Multiplying Rational Expressions

Advanced25 min

Dividing Rational Expressions

Advanced25 min