Reflections
Reflecting a Point Across the X-Axis
Reflect the point $A(3, 5)$ across the x-axis.
Identify the line of reflection: The line of reflection is the x-axis (the horizontal line $y = 0$) = Line: x-axis
Apply the reflection rule: For reflection across the x-axis: $(x, y) \rightarrow (x, -y)$ = Keep x, negate y
Calculate the new coordinates: $A(3, 5) \rightarrow A'(3, -5)$ = $A'(3, -5)$
Verify the reflection: Point $A$ is 5 units above the x-axis. Point $A'$ is 5 units below the x-axis. Both are equidistant from the line of reflection. = Verified
Answer: The reflected point is $A'(3, -5)$
Reflecting a Point Across the Y-Axis
Reflect the point $B(-4, 2)$ across the y-axis.
Identify the line of reflection: The line of reflection is the y-axis (the vertical line $x = 0$) = Line: y-axis
Apply the reflection rule: For reflection across the y-axis: $(x, y) \rightarrow (-x, y)$ = Negate x, keep y
Calculate the new coordinates: $B(-4, 2) \rightarrow B'(4, 2)$ = $B'(4, 2)$
Verify the reflection: Point $B$ is 4 units left of the y-axis. Point $B'$ is 4 units right of the y-axis. Equal distances from the line. = Verified
Answer: The reflected point is $B'(4, 2)$
Reflecting a Triangle Across the Y-Axis
Triangle $PQR$ has vertices $P(1, 3)$, $Q(4, 3)$, and $R(2, 6)$. Reflect the triangle across the y-axis.
Write the reflection rule: For y-axis reflection: $(x, y) \rightarrow (-x, y)$ = Negate x-coordinates
Reflect point P: $P(1, 3) \rightarrow P'(-1, 3)$ = $P'(-1, 3)$
Reflect point Q: $Q(4, 3) \rightarrow Q'(-4, 3)$ = $Q'(-4, 3)$
Reflect point R: $R(2, 6) \rightarrow R'(-2, 6)$ = $R'(-2, 6)$
State the image triangle: Connect the reflected vertices to form triangle $P'Q'R'$ = Triangle $P'Q'R'$
Answer: The reflected triangle has vertices $P'(-1, 3)$, $Q'(-4, 3)$, and $R'(-2, 6)$
Reflecting Across the Line y = x
Reflect the point $C(5, 2)$ across the line $y = x$.
Identify the line of reflection: The line $y = x$ is a diagonal line passing through the origin at a $45°$ angle = Line: $y = x$
Apply the reflection rule: For reflection across $y = x$: $(x, y) \rightarrow (y, x)$ = Swap x and y
Calculate the new coordinates: $C(5, 2) \rightarrow C'(2, 5)$ = $C'(2, 5)$
Verify the reflection: The midpoint of $C$ and $C'$ is $\left(\frac{5+2}{2}, \frac{2+5}{2}\right) = (3.5, 3.5)$, which lies on $y = x$ = Verified
Answer: The reflected point is $C'(2, 5)$
Mistake: Negating the wrong coordinate when reflecting
Why: Students confuse which coordinate changes for each axis. For x-axis reflection, y changes. For y-axis reflection, x changes.
Correct: Remember: reflect across x-axis changes y (vertical flip), reflect across y-axis changes x (horizontal flip)
Mistake: Forgetting the negative sign when reflecting across axes
Why: Students keep the original sign instead of negating the appropriate coordinate.
Correct: Always check: if a point is above the x-axis, its reflection is below (negative y), and vice versa
Mistake: Thinking reflection changes the size of the shape
Why: Students confuse reflection with other transformations like dilation.
Correct: Reflections preserve size and shape. The image is always congruent to the pre-image.
Mistake: Confusing the order of coordinates when reflecting across y = x
Why: Students may not realize that this reflection swaps the x and y values.
Correct: For $y = x$ reflection: just swap the coordinates. $(3, 7)$ becomes $(7, 3)$
Mirror Reflections
When you look in a mirror, you see a reflection of yourself. Your left hand appears as your right hand in the mirror image.
If you stand 60 cm from a mirror, your reflection appears 60 cm behind the mirror surface, so you and your reflection look 120 cm apart.
Symmetric Logo Design
Many company logos use reflectional symmetry to create visually appealing and balanced designs.
The McDonald's 'M' has vertical symmetry - if you reflect the left half across a vertical line, you get the right half.
Kaleidoscope Patterns
Kaleidoscopes create beautiful patterns by reflecting objects across multiple lines, producing symmetrical designs.
A simple kaleidoscope uses two mirrors at an angle to reflect a small collection of colored beads into a complex pattern.
A reflection flips a figure over a line of reflection, creating a mirror image
For x-axis reflection: $(x, y) \rightarrow (x, -y)$ - negate the y-coordinate
For y-axis reflection: $(x, y) \rightarrow (-x, y)$ - negate the x-coordinate
For reflection across $y = x$: $(x, y) \rightarrow (y, x)$ - swap the coordinates
Reflections preserve size and shape - the image is congruent to the pre-image
Each point and its image are equidistant from the line of reflection
Q: How do I know which coordinate to change?
A: Think about which direction you're flipping. Reflecting across a horizontal line (like the x-axis) flips vertically, so y changes. Reflecting across a vertical line (like the y-axis) flips horizontally, so x changes.
Q: What happens if I reflect a point that is ON the line of reflection?
A: The point stays in the same place! If a point is on the line of reflection, it is its own image. For example, $(0, 5)$ reflected across the y-axis is still $(0, 5)$.
Q: Is a reflection the same as a rotation?
A: No. A reflection creates a mirror image (like flipping), while a rotation turns the figure around a point. However, two reflections can sometimes produce the same result as a rotation.
Reflections
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Reflections
Learn how to reflect shapes across lines of symmetry and understand mirror images in geometry.