Simplifying Trigonometric Expressions

Learn a step-by-step toolbox for simplifying trigonometric expressions: rewrite in sine and cosine, use Pythagorean identities, factor, combine fractions and cancel.

Advanced30 min18 problems
Practice Problems

Definition

Simplifying a trigonometric expression means rewriting it, with known identities and ordinary algebra, as an equal expression that is shorter: fewer terms, fewer different functions, no fractions inside fractions. The value never changes, only the form.

The Toolbox

  1. 1.Rewrite in sine and cosine. Replace tan⁡x=sin⁡xcos⁡x\tan x = \frac{\sin x}{\cos x}, cot⁡x=cos⁡xsin⁡x\cot x = \frac{\cos x}{\sin x}, sec⁡x=1cos⁡x\sec x = \frac{1}{\cos x}, csc⁡x=1sin⁡x\csc x = \frac{1}{\sin x}.
  2. 2.Use a Pythagorean identity. Look for sin⁡2x+cos⁡2x\sin^2 x + \cos^2 x, 1−cos⁡2x1 - \cos^2 x, 1−sin⁡2x1 - \sin^2 x, sec⁡2x−1\sec^2 x - 1 or csc⁡2x−1\csc^2 x - 1:
sin⁡2x+cos⁡2x=11+tan⁡2x=sec⁡2x1+cot⁡2x=csc⁡2x\sin^2 x + \cos^2 x = 1 \qquad 1 + \tan^2 x = \sec^2 x \qquad 1 + \cot^2 x = \csc^2 x
  1. 3.Factor. Take out a common factor (sin⁡x−sin⁡xcos⁡2x=sin⁡x(1−cos⁡2x)\sin x - \sin x\cos^2 x = \sin x(1 - \cos^2 x)) or use the difference of squares (1−cos⁡2x=(1−cos⁡x)(1+cos⁡x)1 - \cos^2 x = (1 - \cos x)(1 + \cos x)).
  2. 4.Combine fractions over a common denominator, exactly as with 1a+1b=a+bab\frac{1}{a} + \frac{1}{b} = \frac{a + b}{ab}.
  3. 5.Cancel common factors (never single terms of a sum).

Example

(1−cos⁡2x)csc⁡x=sin⁡2x⋅1sin⁡x=sin⁡x(1 - \cos^2 x)\csc x = \sin^2 x \cdot \frac{1}{\sin x} = \sin x

Know Your Target, Then Check

When a task names the target form ("in terms of cos⁡x\cos x only", "as one function"), steer toward it. At the end, plug in an angle such as x=40°x = 40°: the original and the simplified expression must give the same number.

Try it now

Which expression is equal to cos⁡xtan⁡x\cos x \tan x?

Worked Examples

Simplify tan⁡xsec⁡x\dfrac{\tan x}{\sec x}.
1

Rewrite tangent and secant in sine and cosine

tan⁡x=sin⁡xcos⁡x\tan x = \frac{\sin x}{\cos x} and sec⁡x=1cos⁡x\sec x = \frac{1}{\cos x} → sin⁡xcos⁡x1cos⁡x\dfrac{\frac{\sin x}{\cos x}}{\frac{1}{\cos x}}
2

Divide by a fraction: multiply by its reciprocal

sin⁡xcos⁡x⋅cos⁡x1\frac{\sin x}{\cos x} \cdot \frac{\cos x}{1} → sin⁡xcos⁡xcos⁡x\frac{\sin x \cos x}{\cos x}
3

Cancel the common factor cos⁡x\cos x

sin⁡xcos⁡xcos⁡x\frac{\sin x \cancel{\cos x}}{\cancel{\cos x}} → sin⁡x\sin x

Common Mistakes

Cancelling a term instead of a factor: sin⁡x+cos⁡xsin⁡x=cos⁡x\dfrac{\sin x + \cos x}{\sin x} = \cos x

Why it's wrong: Only factors of the WHOLE numerator and denominator cancel. Here sin⁡x\sin x is just one term of the sum sin⁡x+cos⁡x\sin x + \cos x. At x=45°x = 45° the left side is 22, while cos⁡45°≈0.71\cos 45° \approx 0.71.

Correct: Split the fraction: sin⁡xsin⁡x+cos⁡xsin⁡x=1+cot⁡x\dfrac{\sin x}{\sin x} + \dfrac{\cos x}{\sin x} = 1 + \cot x.

Dropping the squares: writing 1−sin⁡x=cos⁡x1 - \sin x = \cos x

Why it's wrong: The Pythagorean identity is about squares: sin⁡2x+cos⁡2x=1\sin^2 x + \cos^2 x = 1. Without the squares it is false: at x=30°x = 30°, 1−sin⁡30°=0.51 - \sin 30° = 0.5 but cos⁡30°≈0.87\cos 30° \approx 0.87.

Correct: Only 1−sin⁡2x=cos⁡2x1 - \sin^2 x = \cos^2 x is true. If you see 1−sin⁡x1 - \sin x, think of the difference of squares or a conjugate instead.

Adding fractions by adding denominators: 1sin⁡x+1cos⁡x=2sin⁡x+cos⁡x\dfrac{1}{\sin x} + \dfrac{1}{\cos x} = \dfrac{2}{\sin x + \cos x}

Why it's wrong: Trig fractions follow the same rules as number fractions, and 12+13\frac{1}{2} + \frac{1}{3} is not 25\frac{2}{5}.

Correct: Use the common denominator sin⁡xcos⁡x\sin x \cos x: cos⁡x+sin⁡xsin⁡xcos⁡x\dfrac{\cos x + \sin x}{\sin x \cos x}.

Trusting a check at one special angle such as 45°45°

Why it's wrong: At x=45°x = 45° we have sin⁡x=cos⁡x\sin x = \cos x, so many wrong simplifications (like sin⁡xtan⁡x=cos⁡x\sin x\tan x = \cos x) give the same number there by accident.

Correct: Check with one or two "ordinary" angles, for example 20°20° and 50°50°. A difference proves a mistake; equal values only make the result likely, the algebra proves it.

Interactive Visual

Prove

(1−cos⁡2x)csc⁡x=sin⁡x(1 - \cos^2 x)\csc x = \sin x

  1. Start with the left side

    (1−cos⁡2x)csc⁡x(1 - \cos^2 x)\csc x

Check with numbers

Left side

(1−cos⁡2x)csc⁡x(1 - \cos^2 x)\csc x

= 0.5

Right side

sin⁡x\sin x

= 0.5

Both sides have the same value.

Prove

cos⁡2x−1sin⁡xcos⁡x=−tan⁡x\dfrac{\cos^2 x - 1}{\sin x \cos x} = -\tan x

  1. Start with the left side

    cos⁡2x−1sin⁡xcos⁡x\dfrac{\cos^2 x - 1}{\sin x \cos x}

Which expression comes next?

Check with numbers

Left side

cos⁡2x−1sin⁡xcos⁡x\dfrac{\cos^2 x - 1}{\sin x \cos x}

= -0.5774

Right side

−tan⁡x-\tan x

= -0.5774

Both sides have the same value.

Interactive Sandbox

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Practice Problems

18 problems
Problem 1 of 18
Easy
Which expression is equal to cos⁡xtan⁡x\cos x \tan x?

Why It Matters

Simplifying trigonometric expressions is the everyday skill behind almost everything that comes after basic trigonometry:
  • Proving identities: every proof is a chain of simplification steps, so this lesson is the warm-up for the next one
  • Solving trig equations: an equation like sin⁡xcot⁡x=0.5\sin x\cot x = 0.5 is only solvable after you see that it says cos⁡x=0.5\cos x = 0.5
  • Calculus: derivatives and integrals of trig functions are much easier after simplifying, for example sin⁡2x1−cos⁡x=1+cos⁡x\frac{\sin^2 x}{1 - \cos x} = 1 + \cos x
  • Physics and engineering: formulas for forces, waves and circuits shrink to one function, which means fewer mistakes and faster computing
A long expression and its simplified form have the same value, but only the short one shows you what is really going on.

Real World Applications

Engineering Formulas

Engineers often get force and stress formulas as long trigonometric expressions after combining several parts. Simplifying first makes the numbers easy and reduces errors.

Example:

A force on a slanted beam comes out as F=50(1−cos⁡2θ)csc⁡θF = 50(1 - \cos^2\theta)\csc\theta newtons. Since (1−cos⁡2θ)csc⁡θ=sin⁡θ(1 - \cos^2\theta)\csc\theta = \sin\theta, this is just F=50sin⁡θF = 50\sin\theta.

1Try It Yourself

An engineer's formula gives the force F=50(1−cos⁡2θ)csc⁡θF = 50(1 - \cos^2\theta)\csc\theta newtons on a beam tilted at θ=30°\theta = 30°.

How large is the force in newtons?

Step 1: Write the mathematical expression

Simplify first: F=50sin⁡θF = 50\sin\theta. Enter the force:

Faster Code in Games and Graphics

Game engines compute trig expressions millions of times per second. Every function call saved by simplifying makes the program faster.

Example:

A rotation routine computes sin⁡xtan⁡x\dfrac{\sin x}{\tan x} in every frame. Since sin⁡xtan⁡x=sin⁡x⋅cos⁡xsin⁡x=cos⁡x\dfrac{\sin x}{\tan x} = \sin x \cdot \dfrac{\cos x}{\sin x} = \cos x, two function calls and a division become one call.

2Try It Yourself

A programmer replaces sin⁡xtan⁡x\dfrac{\sin x}{\tan x} in a game loop by its simplified form cos⁡x\cos x.

What value does the simplified code return for x=60°x = 60°?

Step 1: Write the mathematical expression

Evaluate the simplified form cos⁡x\cos x at x=60°x = 60°:

Ramps and Slopes in Construction

Builders and surveyors work with the rise of a ramp over a horizontal distance. Spreadsheet formulas built from several steps often hide a simple tangent.

Example:

A spreadsheet computes the rise of a ramp as h=dsin⁡xsec⁡xh = d\sin x\sec x, where dd is the horizontal run. Because sin⁡xsec⁡x=sin⁡xcos⁡x=tan⁡x\sin x \sec x = \frac{\sin x}{\cos x} = \tan x, the formula is really h=dtan⁡xh = d\tan x.

3Try It Yourself

A ramp has a horizontal run of d=12d = 12 m and an angle of x=45°x = 45°. The spreadsheet uses h=dsin⁡xsec⁡xh = d\sin x\sec x.

How high does the ramp rise, in meters?

Step 1: Write the mathematical expression

Simplify to h=dtan⁡xh = d\tan x and enter the rise:

Key Takeaways

  • 1Simplifying changes the form of a trig expression, never its value
  • 2First move when stuck: rewrite tan⁡\tan, cot⁡\cot, sec⁡\sec and csc⁡\csc in terms of sin⁡\sin and cos⁡\cos
  • 3Look for Pythagorean patterns: 1−cos⁡2x=sin⁡2x1 - \cos^2 x = \sin^2 x, 1−sin⁡2x=cos⁡2x1 - \sin^2 x = \cos^2 x, sec⁡2x−1=tan⁡2x\sec^2 x - 1 = \tan^2 x
  • 4Factor (common factor or difference of squares) before you cancel, and cancel only factors, never terms
  • 5Add trig fractions over a common denominator, just like number fractions
  • 6Check the result by plugging an ordinary angle such as 40°40° into both forms: the values must match

Frequently Asked Questions

Usually when it has as few terms and as few different functions as possible, with no fraction inside a fraction. If the task names a target ("in terms of sin⁡x\sin x", "as one function"), stop when you reach that form.
Usually when it has as few terms and as few different functions as possible, with no fraction inside a fraction. If the task names a target ("in terms of sin⁡x\sin x", "as one function"), stop when you reach that form.
It is the safest general strategy, because then only two functions are left and the Pythagorean identity sin⁡2x+cos⁡2x=1\sin^2 x + \cos^2 x = 1 applies. Sometimes a shortcut is faster, for example sec⁡2x−1=tan⁡2x\sec^2 x - 1 = \tan^2 x directly.
It is a great way to catch mistakes: if the two forms give different values at the same angle, something is wrong. But equal values at one or two angles do not prove the simplification, the algebra steps do.
Cancelling a factor is only allowed where that factor is not zero. The original expression is undefined there, while the simplified one may not be, so strictly the two agree everywhere except at those angles.

Glossary

Identity
An equation that is true for every value of the variable where both sides are defined, such as sin⁡2x+cos⁡2x=1\sin^2 x + \cos^2 x = 1
Simplified form
An equal expression with fewer terms, fewer different functions and no nested fractions
Common denominator
A shared denominator that lets you add or subtract fractions, for example sin⁡xcos⁡x\sin x \cos x for 1sin⁡x\frac{1}{\sin x} and 1cos⁡x\frac{1}{\cos x}
Factor
To write a sum as a product, for example sin⁡x−sin⁡xcos⁡2x=sin⁡x(1−cos⁡2x)\sin x - \sin x \cos^2 x = \sin x(1 - \cos^2 x)
Difference of squares
The pattern a2−b2=(a−b)(a+b)a^2 - b^2 = (a - b)(a + b), for example 1−cos⁡2x=(1−cos⁡x)(1+cos⁡x)1 - \cos^2 x = (1 - \cos x)(1 + \cos x)

Formula Card

Sine and Cosine Form

tan⁡x=sin⁡xcos⁡x,  cot⁡x=cos⁡xsin⁡x,  sec⁡x=1cos⁡x,  csc⁡x=1sin⁡x\tan x = \frac{\sin x}{\cos x}, \; \cot x = \frac{\cos x}{\sin x}, \; \sec x = \frac{1}{\cos x}, \; \csc x = \frac{1}{\sin x}

The first move when you are stuck

Pythagorean Identities

sin⁡2x+cos⁡2x=1,  1+tan⁡2x=sec⁡2x,  1+cot⁡2x=csc⁡2x\sin^2 x + \cos^2 x = 1, \; 1 + \tan^2 x = \sec^2 x, \; 1 + \cot^2 x = \csc^2 x

Also in the forms $1 - \cos^2 x = \sin^2 x$ and $\sec^2 x - 1 = \tan^2 x$

Difference of Squares

a2−b2=(a−b)(a+b)a^2 - b^2 = (a - b)(a + b)

For example $1 - \sin^2 x = (1 - \sin x)(1 + \sin x)$

Adding Fractions

ab+cd=ad+bcbd\frac{a}{b} + \frac{c}{d} = \frac{ad + bc}{bd}

Same rule for trig fractions

Today's challengeOne problem, three tries

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