Product Rule for Exponents

Learn why multiplying powers with the same base means adding the exponents, with numbers, variables and coefficients.

Intermediate20 min18 problems
Practice Problems

Definition

The product rule for exponents says: when you multiply two powers with the same base, keep the base and add the exponents.
am⋅an=am+na^m \cdot a^n = a^{m+n}
Why it works: count the factors. 232^3 means three factors of 22, and 242^4 means four factors of 22. Multiplying the two powers puts all the factors in one row:
23⋅24=(2⋅2⋅2)⏟3 factors⋅(2⋅2⋅2⋅2)⏟4 factors=272^3 \cdot 2^4 = \underbrace{(2 \cdot 2 \cdot 2)}_{3 \text{ factors}} \cdot \underbrace{(2 \cdot 2 \cdot 2 \cdot 2)}_{4 \text{ factors}} = 2^{7}
Three factors and four factors make seven factors, so the exponents add: 3+4=73 + 4 = 7. Check with numbers: 8⋅16=128=278 \cdot 16 = 128 = 2^7.
Remember:
  • The base stays the same: 23⋅24=272^3 \cdot 2^4 = 2^7, never 474^7.
  • The exponents are added, not multiplied: 272^7, not 2122^{12}.
  • The bases must be equal: 23⋅522^3 \cdot 5^2 cannot be written as one power.
  • A base with no written exponent has the exponent 11: x=x1x = x^1.

Try it now

Which expression is equal to 52⋅565^2 \cdot 5^6?

Worked Examples

Simplify 32⋅353^2 \cdot 3^5 and check the result.
1

Check the bases

Both powers have the base 33 → Same base, so the product rule applies
2

Add the exponents

32⋅35=32+53^2 \cdot 3^5 = 3^{2+5} → 373^7
3

Check by counting factors

(3⋅3)⋅(3⋅3⋅3⋅3⋅3)(3 \cdot 3) \cdot (3 \cdot 3 \cdot 3 \cdot 3 \cdot 3) has 2+5=72 + 5 = 7 factors of 33 → 373^7 ✓
4

Check with numbers

32=93^2 = 9, 35=2433^5 = 243, 9⋅243=21879 \cdot 243 = 2187 → 37=21873^7 = 2187 ✓

Common Mistakes

Multiplying the exponents: 23⋅24=2122^3 \cdot 2^4 = 2^{12}

Why it's wrong: The exponents count factors. Three factors and four factors are 3+4=73 + 4 = 7 factors, not 3⋅4=123 \cdot 4 = 12. Check: 8⋅16=1288 \cdot 16 = 128, but 212=40962^{12} = 4096. Multiplying exponents belongs to a power of a power, like (23)4(2^3)^4.

Correct: 23⋅24=23+4=27=1282^3 \cdot 2^4 = 2^{3+4} = 2^7 = 128

Multiplying the bases: 23⋅24=472^3 \cdot 2^4 = 4^7

Why it's wrong: Every factor in the row is still a 22. Nothing turns into a 44. And 47=16 3844^7 = 16\,384, far more than the real product 128128.

Correct: Keep the base: 23⋅24=272^3 \cdot 2^4 = 2^7

Adding exponents of different bases: 23⋅32=652^3 \cdot 3^2 = 6^5 or 555^5

Why it's wrong: The product rule needs the same base, because only then do all the factors match. 23⋅32=8⋅9=722^3 \cdot 3^2 = 8 \cdot 9 = 72, while 65=77766^5 = 7776.

Correct: Leave it as 23⋅322^3 \cdot 3^2 or calculate it: 8⋅9=728 \cdot 9 = 72

Adding the coefficients: 3x2⋅4x3=7x53x^2 \cdot 4x^3 = 7x^5

Why it's wrong: The coefficients 33 and 44 are ordinary factors, so they are multiplied. Only the exponents of the same base are added.

Correct: 3x2⋅4x3=(3⋅4) x2+3=12x53x^2 \cdot 4x^3 = (3 \cdot 4)\,x^{2+3} = 12x^5

Interactive Visual

Exponents as repeated factors

Product rule

Same base, multiply: add the exponents.

23⋅242^{3} \cdot 2^{4}

Write each power as repeated factors

22·22·22
232^{3}3 factors
·
22·22·22·22
242^{4}4 factors

3 + 4 = 7 factors in all

Result

23⋅24\displaystyle 2^{3} \cdot 2^{4}==23+4\displaystyle 2^{3 + 4}==27\displaystyle 2^{7}

Value: 27=1282^{7} = 128

Order of Operations

  1. 1. Parentheses
  2. 2. Exponents
  3. 3. × and ÷
  4. 4. + and −
23×24\colorbox{#fde68a}{$\color{#1f2937}2^{3}$} \times 2^{4}

Exponents next: 23=82^{3} = 8

Step 1 of 3

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Practice Problems

18 problems
Problem 1 of 18
Easy
Which expression is equal to 52⋅565^2 \cdot 5^6?

Why It Matters

The product rule saves you from writing out long rows of factors, and it shows up all over math and science:
  • Scientific notation: 103⋅104=10710^3 \cdot 10^4 = 10^7, so a thousand times ten thousand is ten million.
  • Computer memory: 2102^{10} bytes make a kilobyte and 2102^{10} kilobytes make a megabyte, so a megabyte is 210⋅210=2202^{10} \cdot 2^{10} = 2^{20} bytes.
  • Repeated doubling: something that doubles 3 times and then 4 more times has grown 23⋅24=27=1282^3 \cdot 2^4 = 2^7 = 128 times.
  • Algebra: areas and volumes like x2⋅xx^2 \cdot x or 3x2⋅4x33x^2 \cdot 4x^3 must be simplified before you can solve equations or work with polynomials.
It is also the rule the others are built on: the quotient rule and the power of a power follow from counting factors in exactly the same way.

Real World Applications

Computer Memory

Computers count memory in powers of 2, so memory sizes are multiplied with the product rule.

Example:

A kilobyte is 2102^{10} bytes and a megabyte is 2102^{10} kilobytes, so a megabyte is 210⋅210=2202^{10} \cdot 2^{10} = 2^{20} bytes.

1Try It Yourself

A file is stored in 262^6 blocks, and every block holds 2102^{10} bytes.

How many bytes does the file take up?

Step 1: Write the mathematical expression

Multiply the number of blocks by the bytes per block, 26⋅2102^6 \cdot 2^{10}, and give the result:

Counting in Powers of Ten

Large counts in shops and warehouses are easy to handle as powers of 10.

Example:

10210^2 boxes with 10310^3 screws each hold 102⋅103=105=100 00010^2 \cdot 10^3 = 10^5 = 100\,000 screws.

2Try It Yourself

A warehouse has 10210^2 shelves. Each shelf holds 10310^3 boxes, and each box holds 1010 pens.

How many pens are in the warehouse?

Step 1: Write the mathematical expression

Multiply all three numbers, 102⋅103⋅1010^2 \cdot 10^3 \cdot 10, and give the result:

Folding Paper

Every fold doubles the layers of a sheet of paper, so the number of layers grows in powers of 2.

Example:

After 2 folds there are 22=42^2 = 4 layers, after 3 folds there are 23=82^3 = 8 layers.

3Try It Yourself

You fold a sheet of paper in half 3 times. Then you fold the stack in half 4 more times.

How many layers of paper are there at the end?

Step 1: Write the mathematical expression

The first folds give 232^3 layers, and the next folds multiply that by 242^4:

Key Takeaways

  • 1Product rule: am⋅an=am+na^m \cdot a^n = a^{m+n}. Same base, add the exponents.
  • 2It works because you count factors: 23⋅242^3 \cdot 2^4 has 3+4=73 + 4 = 7 factors of 22.
  • 3The base stays the same: 23⋅24=272^3 \cdot 2^4 = 2^7, not 474^7.
  • 4The exponents are added, not multiplied: 23⋅24=272^3 \cdot 2^4 = 2^7, not 2122^{12}.
  • 5A base with no written exponent has the exponent 1: x⋅x4=x5x \cdot x^4 = x^5.
  • 6With coefficients, multiply the numbers and add the exponents of each base: 3x2⋅4x3=12x53x^2 \cdot 4x^3 = 12x^5. Different bases stay separate.

Frequently Asked Questions

Each exponent counts factors. 232^3 is 3 factors of 2 and 242^4 is 4 more factors of 2, so together there are 3+4=73 + 4 = 7 factors: 272^7. Multiplying exponents belongs to a different situation, a power raised to a power like (23)4(2^3)^4, which has its own lesson.
Each exponent counts factors. 232^3 is 3 factors of 2 and 242^4 is 4 more factors of 2, so together there are 3+4=73 + 4 = 7 factors: 272^7. Multiplying exponents belongs to a different situation, a power raised to a power like (23)4(2^3)^4, which has its own lesson.
Yes. Add all the exponents: 2⋅22⋅23=21+2+3=26=642 \cdot 2^2 \cdot 2^3 = 2^{1+2+3} = 2^6 = 64.
No, the bases are different, so you cannot add the exponents. Here the exponents happen to be equal, and then a different rule helps: 23⋅33=(2⋅3)3=63=2162^3 \cdot 3^3 = (2 \cdot 3)^3 = 6^3 = 216. Check: 8⋅27=2168 \cdot 27 = 216. With different bases and different exponents, like 23⋅322^3 \cdot 3^2, just calculate: 8⋅9=728 \cdot 9 = 72.
No. The product rule is only for multiplication. 23+24=8+16=242^3 + 2^4 = 8 + 16 = 24, while 27=1282^7 = 128.

Glossary

Base
The number or variable that is multiplied by itself. In x5x^5 the base is xx.
Exponent
The small raised number that says how many factors of the base there are. In x5x^5 the exponent is 55.
Power
A base with an exponent, like 272^7, or its value, 128128.
Factor
Each number or variable that is multiplied in a product. 23=2⋅2⋅22^3 = 2 \cdot 2 \cdot 2 has three factors of 22.
Coefficient
The number in front of a variable. In 12x512x^5 the coefficient is 1212.
Product rule
To multiply powers with the same base, keep the base and add the exponents: am⋅an=am+na^m \cdot a^n = a^{m+n}.

Formula Card

Product rule

am⋅an=am+na^m \cdot a^n = a^{m+n}

Same base: keep the base, add the exponents.

Three or more powers

am⋅an⋅ap=am+n+pa^m \cdot a^n \cdot a^p = a^{m+n+p}

Add all the exponents of the same base.

Hidden exponent

a=a1a = a^1

A base with no written exponent counts as exponent 1.

With coefficients

c am⋅d an=(c⋅d) am+nc\,a^m \cdot d\,a^n = (c \cdot d)\,a^{m+n}

Multiply the coefficients, add the exponents.

Today's challengeOne problem, three tries

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