Volume of Pyramids

Learn how to find the volume of square, rectangular and triangular pyramids with V = (1/3)Bh, and how to get the height from the slant height.

Advanced25 min18 problems
Practice Problems

Definition

A pyramid is a 3D shape with one flat base (a polygon) and triangular faces that all meet at one point at the top, called the apex.
The volume of every pyramid follows one rule:
V=13BhV = \frac{1}{3}Bh
Where:
  • BB = the area of the base (always find this first)
  • hh = the perpendicular height: the straight vertical distance from the apex down to the base, at a right angle to it

Finding B for Different Bases

BaseBase area BBVolume
Square, side ssB=s2B = s^2V=13s2hV = \frac{1}{3}s^2h
Rectangle, ll by wwB=l×wB = l \times wV=13lwhV = \frac{1}{3}lwh
Triangle, base bb, height hbh_bB=12×b×hbB = \frac{1}{2} \times b \times h_bV=13×12bhb×hV = \frac{1}{3} \times \frac{1}{2}bh_b \times h

Why One Third?

Take a prism and a pyramid with the same base and the same height. The pyramid holds exactly one third of the prism: you can pour three full pyramids of sand into the prism. So
Vpyramid=13Vprism=13BhV_{\text{pyramid}} = \frac{1}{3}V_{\text{prism}} = \frac{1}{3}Bh

Height vs. Slant Height

The slant height ll runs along a triangular face, from the apex to the middle of a base edge. It is longer than hh. In a square pyramid, hh, half the side and ll form a right triangle, so
h2+(s2)2=l2h^2 + \left(\frac{s}{2}\right)^2 = l^2

Try it now

Which formula gives the volume of any pyramid? (BB = base area, hh = height)

Worked Examples

A pyramid has a square base with sides of 66 cm and a perpendicular height of 1010 cm. What is its volume?
1

Find the base area

B=s2=62=36B = s^2 = 6^2 = 36 → B=36B = 36 cm²
2

Multiply by the height

B×h=36×10=360B \times h = 36 \times 10 = 360 → 360360 (this would be the prism)
3

Take one third

V=13×360=120V = \frac{1}{3} \times 360 = 120 → V=120V = 120 cm³

Common Mistakes

Forgetting the 13\frac{1}{3} and calculating V=BhV = Bh

Why it's wrong: BhBh is the volume of the prism with the same base and height. A pyramid fills only one third of it.

Correct: Always finish with ÷3\div 3: a square pyramid with s=6s = 6 and h=10h = 10 has V=360÷3=120V = 360 \div 3 = 120, not 360360.

Using the slant height instead of the perpendicular height

Why it's wrong: The slant height runs along a sloping face, so it is longer than the true height. Using it makes the volume too big.

Correct: Use the height that meets the base at a right angle. If only the slant height is given, find hh with h2+(s2)2=l2h^2 + \left(\frac{s}{2}\right)^2 = l^2.

Putting a side length in place of the base area

Why it's wrong: BB is an area, not a length. Writing 13×6×10\frac{1}{3} \times 6 \times 10 for a square base of side 66 leaves out a whole factor.

Correct: Compute BB first: B=62=36B = 6^2 = 36, then V=13×36×10=120V = \frac{1}{3} \times 36 \times 10 = 120.

Forgetting the 12\frac{1}{2} in a triangular base

Why it's wrong: The area of a triangle is half of base times height, so b×hbb \times h_b alone is twice too big.

Correct: For a triangular base with b=6b = 6 and hb=4h_b = 4: B=12×6×4=12B = \frac{1}{2} \times 6 \times 4 = 12, not 2424.

Interactive Visual

3D Shape Viewer

Faces

5

Edges

8

Vertices

5

Euler's formula: V − E + F = 5 − 8 + 5 = 2

Volume

V = ⅓Bh

V = ⅓ · 6² · 10 = 120

120 cm³

Surface Area

SA = B + ½Pl

SA = 6² + ½ · 24 · 10.44 ≈ 161.28

161.28 cm²

l = √(10² + 3²) ≈ 10.44

3D Shape Viewer

Faces

4

Edges

6

Vertices

4

Euler's formula: V − E + F = 4 − 6 + 4 = 2

Volume

V = ⅓Bh

V = ⅓ · 12 · 9 = 36

36 cm³

Surface Area

SA = B + ½(a·l₁ + b·l₂ + c·l₃)

SA = 12 + ½(6 · 9.1 + 5 · 9.14 + 5 · 9.14) ≈ 85

85 cm²

B = ½ · 6 · 4 = 12

l₁ = √(9² + 1.33²) ≈ 9.1

l₂ = √(9² + 1.6²) ≈ 9.14

l₃ = √(9² + 1.6²) ≈ 9.14

Interactive Sandbox

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Practice Problems

18 problems
Problem 1 of 18
Easy
Which formula gives the volume of any pyramid? (BB = base area, hh = height)

Why It Matters

Pyramid shapes are everywhere, and their volume tells you how much space, air or material they hold:
  • Ancient monuments: the Great Pyramid of Giza holds about 2.6 million cubic meters of stone
  • Modern buildings: the glass pyramid of the Louvre in Paris has a volume of about 90009000 m³ of air to heat or cool
  • Camping: a pyramid tent's volume tells you how much space you have inside
  • Roofs: builders estimate attic space and the air to heat under a pyramid roof
  • Packaging and food: pyramid tea bags, chocolates and candles
The same one-third idea also gives the volume of a cone, so learning it here helps you with every pointed solid.

Real World Applications

The Great Pyramid of Giza

Historians estimate how much stone the Egyptians moved by treating the Great Pyramid as a square pyramid.

Example:

When it was built, the pyramid had a square base of about 230230 m per side and was about 147147 m tall.

1Try It Yourself

Use a square base of 230230 m per side and a height of 147147 m for the Great Pyramid.

What was its volume in cubic meters?

Step 1: Write the mathematical expression

Base area times height, divided by 3:

Pyramid Tents

Camping gear makers give the inside volume of tents so you can compare how roomy they are.

Example:

A tent with a square floor of 22 m by 22 m and a center pole of 1.51.5 m is a square pyramid.

2Try It Yourself

A pyramid tent has a square floor with sides of 22 m. Its center pole is 1.51.5 m tall.

How much air is inside the tent?

Step 1: Write the mathematical expression

Calculate 13×22×1.5\frac{1}{3} \times 2^2 \times 1.5:

Pyramid Roofs

Heating engineers need the volume of the air space under a roof to size a heater or a ventilation fan.

Example:

A pyramid roof (hip roof that ends in one point) sits on a house with a rectangular floor plan.

3Try It Yourself

A pyramid roof covers a rectangular house of 1010 m by 99 m. The top of the roof is 44 m above the ceiling.

What is the volume of the attic space?

Step 1: Write the mathematical expression

Calculate 13×10×9×4\frac{1}{3} \times 10 \times 9 \times 4:

Key Takeaways

  • 1The volume of any pyramid is V=13BhV = \frac{1}{3}Bh, where BB is the base area and hh the perpendicular height
  • 2Find BB first: s2s^2 for a square, l×wl \times w for a rectangle, 12×b×hb\frac{1}{2} \times b \times h_b for a triangle
  • 3A pyramid holds exactly one third of the prism with the same base and height
  • 4Use the perpendicular height, not the slant height; if needed, find it with h2+(s2)2=l2h^2 + \left(\frac{s}{2}\right)^2 = l^2
  • 5To find the height from the volume, use h=3VBh = \frac{3V}{B}
  • 6Volume is always in cubic units (cm³, m³)

Frequently Asked Questions

A pyramid narrows to a point, so it holds less than a prism with the same base and height. Experiments with sand or water show that exactly three pyramids fill the prism. It can also be proven: a cube can be cut into three identical pyramids that each have one face of the cube as their base.
A pyramid narrows to a point, so it holds less than a prism with the same base and height. Experiments with sand or water show that exactly three pyramids fill the prism. It can also be proven: a cube can be cut into three identical pyramids that each have one face of the cube as their base.
Yes. A cone is like a pyramid with a circular base, so V=13BhV = \frac{1}{3}Bh with B=πr2B = \pi r^2 gives V=13πr2hV = \frac{1}{3}\pi r^2 h, the same one-third rule.
Yes. A leaning (oblique) pyramid has the same volume as a straight one with the same base and the same perpendicular height. Only measure hh straight up from the level of the base to the apex.
The formula V=13BhV = \frac{1}{3}Bh works for any base. The only change is how you find BB: split the polygon into triangles or use its area formula, then multiply by hh and divide by 3.

Glossary

Pyramid
A 3D shape with a polygon base and triangular faces that meet at one point (the apex)
Apex
The top point of a pyramid where all the triangular faces meet
Base area (B)
The area of the pyramid's base, measured in square units
Perpendicular height (h)
The straight distance from the apex to the base, meeting the base at a right angle
Slant height (l)
The distance from the apex to the middle of a base edge, measured along a triangular face

Formula Card

Any pyramid

V=13BhV = \frac{1}{3}Bh

One third of base area times perpendicular height

Square base

V=13s2hV = \frac{1}{3}s^2h

The base area is the side squared

Rectangular base

V=13lwhV = \frac{1}{3}lwh

The base area is length times width

Triangular base

V=13×12bhb×hV = \frac{1}{3} \times \frac{1}{2}bh_b \times h

Half of the triangle's base times its height gives B

Height from slant height

h2+(s2)2=l2h^2 + \left(\frac{s}{2}\right)^2 = l^2

Pythagoras in a square pyramid

Height from volume

h=3VBh = \frac{3V}{B}

Multiply the volume by 3, then divide by the base area

Today's challengeOne problem, three tries

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